5 log 4³ × 2³ log √3 × 3 log √5 5 log 4³ × 2³ log √3 × 3 log √5
1. 5 log 4³ × 2³ log √3 × 3 log √5 5 log 4³ × 2³ log √3 × 3 log √5
'5 log 4³ x 2³ log 3^(1/2) x ³ log 5^(1/2) =
3('5 log 4) x (1/2)/3.² log 3 x (1/2).³ log 5 =
3('5 log 4) x (1/6).² log 3 x (1/2).³ log 5 =
3 x (1/6) x (1/2).² log 3 x ³ log 5 x '5 log 4 =.
(1/4).² log 4 =
(1/4).2 = 2/4 = 1/2
2. 5 log 4³ × 2³ log √3 × 3 log √5 5 log 4³ × 2³ log √3 × 3 log √5
Silahkan di cek. Semoga bermanfaat
3. 2 log(3) × 3 log(6) × 5 log(8) per 5 log (3) + 5 log (2)
Bab Logaritma
Matematika SMA Kelas X
( ²log 3 . ³log 6 . ⁵log 8) / (⁵log 3 + ⁵log 2) = (²log 8 . ⁵log 6) / (⁵log (2 . 3))
= (²log 2³ . ⁵log 6) / (⁵log 6)
= 3 . ²log 2
= 3Mapel : Matematika
Kategori : Logaritma
Kelas : SMA / MA kelas X
Semester : Ganjil
Pembahasan:
[tex]\frac{^2log 3 .^3log 6 .^5log 8}{^5log 3 + ^5log 2} [/tex]
[tex]=\frac{^2log 8 .^5log 6}{^5log (2 . 3)} [/tex]
[tex]= \frac{^2log 2^3 . ^5log 6}{^5log 6} [/tex]
[tex]= 3 .^2log 2 [/tex]
[tex]= 3[/tex]
4. Buktikan pertanyaan ini. (2^log 5 +3^log 5)6^log 5 / 2^log 5 . 3^log 5 = 7
tc cv jeff. gak mau kan biar bpk, dengan x factor indonesia yang mempengaruhi cepat sembuh ya sayang ku wong cilik
5. 5 log 75 + 3 log 54 - 5 log 3 - 3 log 2
5log 75 + 3log 54 - 5log 3 - 3log 2
5log (25×3) + 5log 3 + 3log (9×6) - 5log 3 - 3log 2.
5log 25 + 5log 3 + 3log 9 + 3log 6 - 5log 3 - 3log 2.
* 5 log 3 di coret karena sama, jadi sisa.
5 log 25 + 3log 9 + 3log 6 - 3log 2.
5log 5² + 3 log 3² + 3log (2×3) - 3log 2.
5 log 5 coret dan 3 log 3 coret, jadi sisa. 2+2 3log 2 - 3log 2
3log 2 dan 3 log 2 di coret, jadi sisa.
2 + 2 = 4.
jadi 5log 75 + 3log 54 - 5log 3 - 3log 2 adalah 4
penjelasan lengkapnya ada dalam gambar
6. 1. 5 log 1 + 5 log 50 2. 27 log 3 3. 2 log 25 × 5 log 3 × 3 log 32
Jawaban:
2.²⁷log 3
= (3³)'log 3
= 1/3
3.= ²log 25 x ⁵log 3 x ³log 32
= ²log 5² x ⁵log 3 x ³log 32
= 2 • ²log 5 x ⁵log 3 x ³log 32
= 2 • ²log 32
= 2 • ²log 2⁵
= (2 x 5) • ²log 2
= 10 • 1
= 10
7. nilai dari 3 log 3 . 6 log 8 . 5 log 6 . 3 log 5 ?
3 log 3. 3 log 5. 5 log 6. 6 log 8
= 3 log 8
8. 5 Log + 3 + 5 Log 4 + 5 Log 1/2 + 3 Log 27
Jawaban:
33 log dan bisa juga 16 karna 32 dibagi 2=16
maaf kalo salah
9. 4 log 5 . 3 log 2 . 5 log 3
Hasil dari
⁴log 5 . ³log2 . ⁵log3
[tex] = {}^{4} log5 \times \frac{ {}^{5} log2 }{ {}^{5} log3} \times {}^{5} log3 \\ \\ = {}^{4} log5 \times {}^{5} log2 \\ \\ = \frac{1}{2} \times {}^{2} log5 \times {}^{5} log2 \\ \\ = \frac{1}{2} [/tex]
____________
Mata pelajaran : Matematika
Kelas : X
Kategori : Bentuk Pangkat, Akar, dan Logaritma
Kata kunci : logaritma
Kode : 10.2.1 [Bentuk Pangkat, Akar, dan Logaritma]
simak soal serupa
brainly.co.id/tugas/16240629
#backtoschoolcampaignMapel : Matematika
Kelas : 10
Materi : Bab 3 - Logaritma
Kata Kunci : -
Kode Kategorisasi : 10.2.3 ( Matematika Kelas 10 Bab 3 - Logaritma )
————————————————————
4log 5 . 3log 2 . 5log 3
= 3log 3 . 5log 5 . ⁴log 2
= 1 . 1 . 1/2
= 1/2 ..... ✔️
Pelajaran Lebih Lanjut ( Internal Link ) :
https://brainly.co.id/tugas/8204364
Semoga bermanfaat.....
-Prisco ( One Punch Man )
#backtoschoolcampaign
10. 3 log7. 2 log 5. 5 log 3=... a. 3 log 7 b. 5 log 7 c. 2 log 7 d. 2 log 3 e. 5 log 3
Jawaban:
3log7 . 2log5 . 5log3
= 3log7 . 2log3
= 2log3 . 3log7
= 2log7 (c)
menggunakan sifat
[tex] {}^{a} logb \: \: . \: \: {}^{b} logc \: = {}^{a} logc[/tex]
11. (2 log 5 + 3 log 5) kali 36 log 0,2 per 2 log 5 kali 3 log 5
Jawaban:
sama dengan 68513 log
Penjelasan dengan langkah-langkah:
mafa kalau salah hehe
12. 2 log 5 . 5 log 3 . 3 log 16
Penjelasan dengan langkah-langkah:
²log5.⁵log3.³log16=²log16=²log2⁴ =4
RUMUS:
a log n.ⁿlog b =a log b
a log aⁿ =n
13. nilai dari 5 log 75 - 3 log 54 - 5 log 3 + 3 log 2 =
5 log 75 - 3 log 54 - 5 log 3 + 3 log 2
= 5 log 75 - 5 log 3 + 3 log 2 - 3 log 54
= 5 log (75/3) + 3 log (2/54)
= 5 log 25 + 3 log 1/27
= 2 + 3 log 1/(3)^3
= 2 + 3 log 3^-3
= 2 + [-3 (3 log 3)]
= 2 - 3(1)
= 2 - 3
= -1
14. 7 log 3. 3 log 5. 5 log 1
[tex]\tt {}^{7} log \: 3 \times {}^{3} log \: 5 \times {}^{5} log \: 1[/tex]
[tex]\tt {}^{7} log \: 3 \times {}^{3} log \: 5 \times 0[/tex]
[tex]\tt {}^{7} log \: 3 \times 0[/tex]
[tex]\boxed{\tt 0}[/tex]
15. Log 3 = 0,4771 Log 5 = 0,6990 Tentukan Log 45 Log 25 Log 135 Log 5/3 Log 3/5
log 45
= log (9 x 5)
= log 9 + log 5
= log 3² + log 5
= 2 . log 3 + log 5
= 2(0,4771) + 0,6990
= 1,6532
log 25
= log 5²
= 2 . log 5
= 2 x 0,6990
= 1,398
log 135
= log (27 x 5)
= log 27 + log 5
= log 3³ + log 5
= 3 . log 3 + log 5
= 3(0,4771) + 0.6990
= 1,4313 + 0,6990
= 2,1303
log 5/3
= log 5 - log 3
= 0,6990 - 0,4771
= 0,2219
log 3/5
= log 3 - log 5
= 0,4771 - 0,6990
= -0,2219
16. ³log 81 + ²log 1/32 - ⁵log 5√5 = ³log 3⁴ + ²log 2⁻⁵ - (⁵log 5¹ + ⁵log √5) = 3 ³log 3 -5 ²log 2 - 1 ⁵log 5 - 1/2 ⁵log 5 = 3 - 5 - 1 - 1/2 = -2 - 1 - 1/2 = -3 - 1/2 = -6/2 - 1/2 = -7/2 Lalu, dari mana anda memperoleh nilai ³log 3⁴ = 3 ³log 3
Jawaban sebenarnya ada di gambar. mungkin si penjawab salah ketik atau kurang fokus
17. log 5 × 5 log 3 × 3 log 8 =
log 5 × 5 log 3 × 3 log 8 =1.3569687712
hasil nya itu kk
18. log 5√5 + log √3 - log 4 √5
log 5√5 + log √3 - log 4√5 = log [tex] \frac{5 \sqrt{5} . \sqrt{3} }{4 \sqrt{5} } [/tex]
= log [tex] \frac{5}{4} \sqrt{3} [/tex]
= log 5 - log 4 + log √3
= log 5 - log 4 + [tex] \frac{1}{2} [/tex].log 3
= 0,6990 - 0,6020 + [tex] \frac{1}{2} [/tex] . 0,3010
= 0,0970 + 0,1505
= 0,2475log (5√5 x √3 : 4√5)=
log (5/4 √3)=
log (5/2².3^1/2)=
1/2.1/2 (log5+log3-log2)=
(log5+log3-log2)/4
19. 3 log 5 × 7 log 3 × 5 log 49
Penjelasan:
3log5 x 5log7² x 7log3
= 2 ³log7 x 7log3
= 2 ³log3
= 2
20. 2 log 5 × 5 log 3 × 3 log 8 =
= 2 log 5 x 5 log 3 x 3 log 8
= 2 log 8
= 3
Semoga Membantu
Jadiin Terbaik Ya Kak
2 log 5×5log 3×3log 8=2 log 8
21. ^4 log 5 × ^5 log 3 × ^3 log 256 adalah...
Sifat Logaritma :
ᵃlog b x ᵇlog c = ᵃlog c
⁴log 5 x ⁵log 3 x ³log 256
= (⁴log 5 x ⁵log 3) x ³log 256
= ⁴log 3 x ³log 256
= ⁴log 256
= ⁴log 4⁴
= 4 . ⁴log 4
= 4
22. (2 log 5+3 log 5) x 6 log 5) :2 log 5 x 3 log 5
Jawaban terdapat pada lampiran.
Dapat menggunakan, alog b = 1/(blog a)
23. 4 log 64 - 5 log 75 - 5 log 5/3 + 3 log 243
Kelas 10 Matematika
Bab Logaritma
⁴log 64 - ⁵log 75 - ⁵log (5/3) + ³log 243
= ⁴log 4³ - (⁵log 75 + ⁵log (5/3)) + ³log 3⁵
= 3 - (⁵log (75 . 5/3)) + 5
= 3 - (⁵log 125) + 5
= 8 - ⁵log 5³
= 8 - 3
= 5
24. nilai dari log 5√5 + log √3 + log 3 ÷ log 15 adalah
jawaban nya 1.692. maaf kalau salah
25. Bagian I 1. Hitunglah 5 log 5; 3 log 9; 4 log 16; log 1. 2. Hitunglah 7 log 49; 5 log 125; 8 log 512; 2 log 0,25. 3. Hitunglah 3 log ⅓; 3 log √3; 9 log √3; 2 log ∛4. 4. Hitunglah √ 5 log 0,2; 6 log ∛36; log √7 ; 3 log 3√3 5. Hitunglah log ⁄ ; ½log 32; 0,1log 0,01; 0,01log 0,1 6. Hitunglah 0,1log 1; log √10 √ ; log 1 2⁄ √ Bagian II Jika log 2 = 0,3010 dan log 3 = 0,4771, hitunglah: 1. Log 4; log 5; log 6; log 8 2. Log 12; log 15; log 18; log 24 3. Log 20; log 2000; log 0,2; log 0,002 4. Log 30; log 300; log 0,03; log 30000 5. Log 60; log 0,6; log 120; log 1,2 6. Log ½; log ⅙; log ⅛; log 4½ 7. Log ½√3; log 3√2; log 2∛3; log √24 Bagian III Hitunglah: 1. Log 2 + log 18 – log 6 + log 5 – log 3 2. Log 8 + 2 log 3 − 3 log √5 + log 10 − log 14,4 − log 3. 3 log 5 ∙ 5 log 3 4. 7 log 4 : 7 log 2 5. 4 log ∛25 ∙ 5 log ⅛ mohon bantuannya
Jawab:
Penjelasan dengan langkah-langkah:
1. ⁵log 5 = 1
³log 9 = ³log 3² = 2
⁴log 16 = ⁴log 4² = 2
log 1 = 0
2. ⁷log 49 = ⁷log 7² = 2
⁵log 125 = ⁵log 5³ = 3
⁸log 512 = ⁸log 8³ = 3
²log 0,25 = ²log 2^(-2) = -2
3. ³log 1/3 = ³log 3^(-1) = -1
³log √3 = ³log 3^(1/2) = 1/2
⁹log √3 = (³^2)log 3^(1/2) = 1/4
²log ∛4 = ²log 2^(2/3) = 2/3
4. √5 log 0,2 = 5^(1/2) log 5^(-1) = -2
6 log ∛36 = 6 log 6^(2/3) = 2/3
log √7 = 0,42
³log 3√3 = 3 log 3^(3/2) = 3/2
5. ½log 32 = 1/2 log (1/2)^(-5) = -5
0,1log 0,01 = 0,1 log 0,01^2 = 2
0,01log 0,1 = 0,01 log 0,01^(1/2) = 1/2
6. 0,1log 1 = 0
log √10 = 0,5
26. 5 log 75 - 3 log 54 - 5 log 3 + 3 log 2 =
= 5 log 75 : 3 - 3 log 54 x 2
= 5 log 25 - 3 log 108
= 5 log 5² - 3 log 2² x 3³
= 2 - 3 log 4 + 3
= - 3 log 4 + 1
27. 4 log 64 - 5 log 75 - 5 log 5/3 + 3 log 243
4 log 64 = 3
5 log 75 - 5 log 5/3 = 5 log 75/ 5/3 = 5 log 45
3 log 243 = 5
4 log 64 - 5 log 75 - 5 log 5/3 + 3 log 243 = 3- 5 log 45 + 5 =8- 5 log 45
28. Hasil dari : 1. ³Log 5 x ⁶²⁵Log 27 = . . . 2. ⁵Log 150 - ⁵Log 24 + ⁵log 4 = . . . 3. 3√3 Log 1 per √27 = . . . 4. Log 2 = 0.301 Log 3 = 0,477 Log 24 = ...? 5. ²Log √5 + 2⁴Log 5 per ²Log 3 x ³Log 5 =... plus caranya >/\
tanya guru aja..... :)
4). log 24 = log ( 6x4 )
= log 6 + log 4 = 2 log 3 + 2 log 2
= 2(0,477) + 2(0,301)
= 0,954 + 0,602 = 1,556
coba di teliti lgi brng x ada yg salah
29. (log² 5 - log 9 . log 5 + log² 3) : (log 3 - log 3)tolong beserta caranya yaa
hasilnya tak terdefinisi..
Lihat pembaginya, yaitu log3 - log3 = 0, berapapun di bagi 0 hasilnya adalag tak terdefinisi..
#semogamembantuya.....
30. 5 log 75 - 3 log 54 - 5 log 3 + 3 log 2 = ?
5 log 75 - 3 log 54 - 5 log 3 + 3 log 2 =
= (5 log 3x25) - (3 log 2x27) - 5 log 3 + 3 log 2
{sifat logaritma p log a.b = p log a + p log b}
= 5 log 3 + 5 log 25 - 3 log 2 + 3 log 27 - 5 log 3 + 3 log 2
= 5 log 3 - 5 log 3 - 3 log 2 + 3 log 2 + 5 log 5^5 + 3 log 3^3
{kelompokkan} {sifat logaritma a log a^n = n . a log a}
= 5 + 3
= 8
